Answer:
a.The probability that two randomly selected tulip bulbs both are red=[tex]\frac{45}{406}[/tex].
b.The probability that the first bulb selected is red and second yellow=[tex]\frac{50}{406}[/tex].
c.The probability that the first bulb selected is yellow and the second red=[tex]\frac{50}{406}[/tex].
d.The probability that one bulb is red and other yellow=[tex]\frac{50}{203}[/tex].
Step-by-step explanation:
Given
Total number of bulbs= 29
Number of bulbs of red=10
Number of yellow bulbs=10
Number of purple bulbs=9
Formula of probability, P(E)=[tex]\frac{favourable \; cases}{total\;number\; of \; cases}[/tex]
a.The probability that two randomly selected tulip bulbs are both red=[tex]\frac{10}{29}\times\frac{9}{28}=\frac{45}{406}[/tex].
b.The probability of getting first bulb is red=[tex]\frac{10}{29}[/tex].
The probability of getting second bulb is yellow=[tex]\frac{10}{28}[/tex]
Hence,the probability that the firs bulb selected is red and the second bulb yellow=[tex]\frac{10}{29}\times\frac{9}{28}=\frac{45}{406}[/tex]
c. The probability of getting firs bulb is yellow =[tex]\frac{10}{29}[/tex]
The probability of getting second bulb is red=[tex]\frac{10}{28}[/tex]
Hence,the probability that the firs bulb selected is yellow and the second bulb red=[tex]\frac{10}{29}\times\frac{10}{28}=\frac{50}{406}[/tex].
d.The probability of getting first bulb is red and second is yellow=[tex]\frac{50}{406}[/tex]
The probability of getting first bulb is yellow and second is red=[tex]\frac{50}{406}[/tex]
The probability that one bulbe is red and other is yellow= probability of getting first bulb is red and other yellow+ probability of getting first bulb is yellow and other is red
Hence, the probability of getting one bulb is red and other is yellow=[tex]\frac{50}{406}+\frac{50}{406}=\frac{50}{203}[/tex]
