Answer:
The rate of flow of nitrogen into the reactor is 2,470.588 kg/h.
Explanation:
Mole percentage of nitrogen gas = 25 mole%
Mole percentage of hydrogen gas = 75 mole%
Average molecular weight of the mixture:
[tex](0.25\times 28 g/mol)+(0.75\times 2 g/mol)=8.5 g/mol[/tex]
Rate of flow of the stream = 3000 kg/h
Mass of stream in 1 hour = 3000 kg = 3,000,000 g
Moles of stream :
[tex]\frac{3000 g}{8.5 g/mol}=352,941.17 mol[/tex]
Moles of nitrogen gas in 352,941.17 moles of stream be x
[tex]25\%=\frac{\text{Moles of nitrogen gas}}{\text{Moles of stream}}\times 100[/tex]
[tex]25=\frac{x}{352,941.17mol}\times 100[/tex]
x = 88,235.294 mol
Mass of 8,823,529.4 mole of nitrogen gas:
[tex]88235.294 mol\times 28 g/mol=2.470588.2 g=2,470.588 kg[/tex]
The rate of flow of nitrogen into the reactor is 2,470.588 kg/h.
