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A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 110,000 kg of scrap metal into it. (a) What is the final velocity of the loaded freight car? (b) How much kinetic energy is lost?

Respuesta :

Explanation:

The mass of freight car, m₁ = 30,000 kg

Velocity of freight car, u₁ = 0.85 m/s

Mass of hopper, m₂ = 110,000 kg

(a) Let v is the final velocity of the loaded freight car. Initial momentum of the car before the dump, [tex]p_i=30000\ kg\times 0.850\ m/s=25500\ kg-m/s[/tex]

Final momentum, [tex]p_f=(30000\ kg+110000\ kg)v=140000\ v[/tex]

According to the conservation of momentum,

initial momentum = final momentum

25500 kg-m/s = 140000 v

v = 0.182 m/s

So, the  final velocity of the loaded freight car is 0.182 m/s.

(b) Initial kinetic energy, [tex]k_i=\dfrac{1}{2}\times 30000\ kg\times (0.850\ m/s)^2=10837.5\ J[/tex]

Final kinetic energy, [tex]k_f=\dfrac{1}{2}(m_1+m_2)v^2[/tex]

[tex]k_f=\dfrac{1}{2}\times (30000\ kg+110000\ kg)\times (0.182\ m/s)^2=2318.68\ J[/tex]

So, loss in kinetic energy, [tex]\Delta k=k_f-k_i[/tex]

[tex]\Delta k=2318.68\ J-10837.5\ J=-8518.82\ J[/tex]

So, 8518.82 J of kinetic energy is lost after collision. Hence, this is the required solution.

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