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Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)β†’2AlCl3(s) What is the maximum mass of aluminum chloride that can be formed when reacting 15.0 g of aluminum with 20.0 g of chlorine? Express your answer to three significant figures and include the appropriate units.

Respuesta :

Answer:

25.1 grams to 3 significant figures.

Explanation:

2Al(s) + 3Cl2(g) β†’ 2AlCl3(s)

Using the molar masses:

2*26.982 g Al Β reacts with 3*2*35.45 g of Cl2

53.964 g Β Al reacts with 212.7 g Cl2

So 15 g Al reacts with (212.7 / 53.964) Β * 15 = 59.123 g Cl2

But we only have 20 g of chlorine so the Β mass of Aluminium which reacts with this is( 53.964/ 212.7) * 20

= 5.074 g.

So the maximum mass of aluminium chloride = 5.074 + 20

= 25.074 g. Β (answer)

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