Respuesta :
Answer:
Velocity = 0.4762 m/s
Explanation:
Given the details for the simple harmonic motion from the question as:
Angular frequency, ω = 12 rad/s
Amplitude, A = 0.060 m
Displacement, y = 0.045 m
The initial Energy =  U  = (1/2) kA²  Â
where A is the amplitude and k is the spring constant.
The final energy is potential and kinetic energy
  K + U =  (1/2) mv²  + (1/2) kx² Â
where  x  is the displacement
m is the mass of the object
v is the speed of the object
Since energy is conservative. So, the final and initial energies are equal  as:
  (1/2) k A²  = (1/2) m v²  + (1/2) kx² Â
Using,  ω² = k/m, we get: Â
Velocity:
[tex]v=\omega\times \sqrt{[ A^2 - y^2 ]}[/tex]
[tex]v=\omega\times \sqrt{[ {0.06}^2 - {0.045}^2 ]}[/tex]
Velocity = 0.4762 m/s
