Answer:
1) Force on top face [tex]=1.09kN[/tex]
2)Force on the side face[tex]=1.539kN[/tex]
Explanation:
a)
We know that
[tex]Force=Pressure\times Area[/tex]
Pressure shall be calculated at a depth of (1-0.45) meters from the top of the water surface
[tex]Pressure=\rho \times g\times h\\\\\therefore Pressure=1000\times 9.81\times (1-0.45)Pa\\\\Pressure=5.395kPa[/tex]
Thus force is calculated as under
[tex]Force=5.395\times (0.45)^{2}\\\\Force=1.09kN[/tex]
b)
The force on one of it's sides is calculated in the same manner except that the pressure is obtained at the centroidal level of the face of cube
Thus
[tex]Force=\rho \times g\times h_{cg}\times Area\\\\Force=1000\times 9.81\times (1-\frac{0.45}{2})\times (0.45)^{2}\\\\Force=1.539kN[/tex]
