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An AC power source has an rms voltage of 1.20x 102 V and operates at a frequency of 60.0 Hz. If a purely inductive circuit is made from the power source and a 47.0 H inductor, determine the rms current in mA through the inductor.

Respuesta :

Answer:

8.127 mA

Explanation:

We have given RMS value of AC voltage =1.2×120=144 V

frequency=60 Hz

inductance = 47 Hz

Inductive reactance  [tex]X_L=2\times \pi \times f\times L[/tex]

[tex]X_L=2\times \pi \times 60\times 47=17718.5825\ ohm[/tex]

current [tex]I=\frac{V}{X_L}=\frac{144}{17718.5825}=0.008127\ A=8.127\ mA[/tex]

So the inductor current will be 8.127 mA

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