Given:
slip direction angle, [tex]\phi = 42.7^{\circ} [/tex]
angle normal to slip plne, [tex]\lambda = 48.3^{\circ} [/tex]
critical resolved shear stress, [tex]\tau_{r} = 29.4 MPa[/tex]
Solution:
To calculate the applied stress, [tex]\sigma_{a}[/tex] the formula for critical resolved shear stress is given by:
[tex]\tau_{r} = \sigma_{a} cos\lambda cos\phi [/tex] Â Â Â Â Â (1)
Putting the given values in eqn (1):
[tex]29.4\times 10^{6} = \sigma_{a} \times cos48.3^{\circ}\times cos 42.7^{\circ} [/tex]
[tex]\sigma _{a} = 60.14 MPa[/tex]
Therefore, necessary applied stress is 60.14 MPa
