Respuesta :
Answer:
The required probability is [tex]\frac{19}{40}[/tex]
Step-by-step explanation:
The probability of obtaining a defective item from container 1 is [tex]P(E_1)=\frac{3}{8}[/tex]
The probability of obtaining a good item from container 1 is [tex]P(E_1)=\frac{5}{8}[/tex]
The probability of obtaining a defective item from container 2 is [tex]P(E_1)=\frac{2}{5}[/tex]
The probability of obtaining a good item from container 2 is [tex]P(E_1)=\frac{3}{5}[/tex]
The cases of the event are
1)Defective item is drawn from container 1 and good item is drawn from container 2
2)Defective item is drawn from container 2 and good item is drawn from container 1
Thus the required probability is the sum of above 2 cases
[tex]P(Event)=\frac{3}{8}\times \frac{3}{5}+\frac{5}{8}\times \frac{2}{5}=\frac{19}{40}[/tex]
