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Crew members attempt to escape from a damaged submarine 141 m below the surface.What force must be applied to a pop-out hatch, which is 1.72 m by 0.859 m, to push it out at that depth? Assume that the density of the ocean water is 1024 kg/m3 and the internal air pressure is at 1.00 atm.

Respuesta :

Answer:

20.9 x 10⁵ N

Explanation:

The external air pressure downwards and internal air pressure upwards will cancel out. TH net pressure to be faced will be due to water column of 141 m depth.

Pressure of water = hdg = 141 x 1024 x 9.8 = 14.15 x 10⁵ Pa

Area of hatch = 1.72 x 0.859 = 1.4775 sq m.

Total force required = area x pressure = 14.15 x 10⁵ x 1.4775 = 20.9 x 10⁵ N.

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