Answer:
k = 7212
W =2705 in-lb
Explanation:
force (F) = 28,848 lb
we know,
a) F = k x ..........................(1)
x = 8 - 4 = 4 inch
from equation (1)
28,848 = k × 4
k = 7212 (assembly force constant)
b) we know
Force at x distance F(x) = 7212x
work done = force × displacement
assume displacement of small distance dx
work done = 7212x dx
for first half inch
[tex]W = \int\limits^{0.5}_0 7212x\ dx\\W = 3606\ [x^2]^{0.5}_0\\W=901.5\ inch-pound[/tex]
hence for second half inch we just multiply first half with 3
W = 3×901.5
W = 2704.5 ≈ 2705 in-lb
