If the work required to stretch a spring 1 ft beyond its natural length is 12 ft-lb, how much work is needed to stretch the same spring from its natural length to 3 in? Hint: 1 ft = 12 in

Respuesta :

Answer:[tex]W=\frac{3}{4} ft-lb[/tex]

Explanation:

Given

Work required to stretch 1 ft is 12 ft-lb

and we have to find work required to stretch 3 in.

i.e. [tex]\frac{1}{4} ft[/tex]

[tex]12=\frac{1}{2}K\left ( 1\right )^2 ------(1)[/tex]

[tex]W=\frac{1}{2}k\left ( \frac{1}{4}\right )^2-----(2)[/tex]

divide (1)&(2)

[tex]\frac{12}{W}=\left ( \frac{4}{1}\right )^2[/tex]

[tex]W=\frac{12}{4\times 4}[/tex]

[tex]W=\frac{3}{4} ft-lb[/tex]

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