Answer:[tex]F=3\times 10^{-5} N[/tex]
Explanation:
Given
[tex]I_1=2 Amps[/tex]
[tex]I_2=0.75 Amps[/tex]
Length of each wires[tex]\left ( L\right )=5 m[/tex]
Distance between wires [tex]\left ( r\right )=5 cm[/tex]
Force per unit length =[tex]\frac{\mu_0I_1I_2}{2\pi r}[/tex]
[tex]F'=\frac{2\times 10^{-7}\times 2\times 0.75}{2\pi \times 0.05}[/tex]
[tex]F'=6\times 10^{-6}[/tex]
Force for [tex]L=5 m[/tex]
[tex]F=3\times 10^{-5} N[/tex]
