Answer:44.58 J
Explanation:
mass of block [tex]\left ( m\right )=2.5 kg[/tex]
Force magnitude=3 N
Initial velocity =[tex]2.3\hat{i} m/s[/tex]
Final velocity=[tex]6.4\hat{j} m/s[/tex]
Initial Kinetic Energy=[tex]\frac{1}{2}mv^2[/tex]
=[tex]\frac{1}{2}\times 2.5\times 2.3^2=6.612 J[/tex]
Final Kinetic Energy=[tex]\frac{1}{2}mv^2[/tex]
=[tex]\frac{1}{2}\times 2.5\times 6.4^2=51.2 J[/tex]
Work Done =Final -Initial Kinetic energy=51.2-6.612=44.58 J
