Answer:
461.54 kg/h
Explanation:
First lets calculate the mass flow of the dry product:
Md=1000 kg/h*(1-0.58) = 420 kg/h
The mass flow of the moist final product is then:
Mm= 420 kg/h /(1-0.22) = 538.46 kg/h
The water to be evaporated is then the difference between the feed and the product.
W= 1000 kg/h - 538.46 kg/h = 461.54 kg/h
