Answer:
7.69 X 10^-6 cubic meters of sea water must be processed to recover 500 mg of bromine.
Step-by-step explanation:
First of all We need to work with consistent units, so let's convert mg of bromine to grams:
500 mg of bromine (divided by 1000) = 0,5g of bromine
So, to find the right answer to this problem we have to apply a direct rule of three:
If there are 65 g of bromine in 1,000,000 grams of sea water, How many grams of sea water is needed to recover 0,5 grams
65g (bromine) _____________ 1,000,000 g (sea water)
0,5g (bromine) ______________ X
X = (0,5 * 1,000,000)/(65)
X = 7.69 g of sea water
But now we need to convert these 7.69 g of sea water to cubic meters.
Sea water density is 1.0 x 10^3 kg/m3 = 1,000 kg/m3
If we multiply this by 1000 to convert kg to grams, We will find that
the equivalent sea water density is: 1.0 x 10^6 g/m3
It means that each cubic meter of sea water weights 1,000,000 g.
So, If one cubic meter of sea water equals to 1,000,000 g of sea water
We need to apply another rule of three to find the final answer:
1,000,000 g __________ 1 m3
7.69g __________ X
X= (7.69* 1)/ 1,000,000
X= 7,69 x 10^-6 m3
