Answer:
1.35 m
Explanation:
t = 3 s
u = 4.5 m/s
a = - 2.7 m/s^2
Let the displacement of the car in time t = 3 s is s.
Use second equation of motion
[tex]s=ut+\frac{1}{2}at^2[/tex]
[tex]s=4.5 \times 3-\frac{1}{2}\times 2.7 \times 3 \times 3[/tex]
s = 1.35 m
Thus, the displacement of car in time 3 s is 1.35 m.
