Answer:
H = 95.3 m
Explanation:
Let the height from which object fall down is H
so the total time to fall is given as
[tex]H = \frac{1}{2}gt^2[/tex]
now it cover 39 m in last 1.02 s of its path
[tex]H - 39 = \frac{1}{2}g(t - 1.02)^2[/tex]
so now we have
[tex]\frac{1}{2}gt^2 - 39 = \frac{1}{2}g(t - 1.02)^2[/tex]
by solving above equation
[tex]t = 4.41 s[/tex]
Now the total height is given as
[tex]H = \frac{1}{2}gt^2[/tex]
[tex]H = \frac{1}{2}g(4.41)^2[/tex]
H = 95.3 m
