Answer: 0.42 mg
Step-by-step explanation:
Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.
Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl = [tex]\dfrac{0.63}{3}[/tex]
[tex]=\dfrac{63}{300}=\dfrac{21}{100}=0.21\ mg[/tex]
Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-
[tex]2\times0.21=0.42\ mg[/tex]
Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg
