Answer:
The answer to your question is: Â 68.3%
Explanation:
Urea = ?
Theoretical yield
Ammonia 145.1 kg
Carbon dioxide = 211.4 kg
Urea = 174.9 kg
MW NH3 = 17kg
MW CO2 44 kg
MW Urea = 60 kg
           2NH₃(aq)   +   CO₂(aq)   →   CH₄N₂O(aq)   +   H₂O(l)
           34             44 kg         60kg
          145.1          211.4          174.9
Limiting reactant = NH3
          34kg of NH3 ------------------ 60 kg of Urea
          145.1 kg    -------------------  x
         x = (145.1 x 60) / 34
        x = 256 kg of Urea
Percent yield = 174.9 / 256 x 100
           = 68.3%
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