Answer:
[tex]F=1.509\times 10^{-16}N[/tex]
Explanation:
We have given that mass of electron [tex]m=9.11\times 10^{-31}kg[/tex]
It is given that initial velocity u=0 m/sec
Final velocity v = [tex]2.7\times 10^6m/sec[/tex]
Distance S = 2.2 cm = 0.022 m
According to third law of motion [tex]v^2=u^2+2as[/tex]
[tex](2.7\times 10^6)^2=0^2+2\times a\times 0.022[/tex]
[tex]a=165.68\times 10^{12}m/sec^2[/tex]
Accelerating force F is given by F = ma
So accelerating force [tex]F=9.11\times 10^{-31}\times 165.68\times 10^{12}=1.509\times 10^{-16}N[/tex]
