if you are given a certain length of wire the biggest area you can fend up is a circle, 2nd a square. For the rectangle to have the biggest area,the difference between the 2 sides must be the minimum, it must approaches a square
then we have 2(l +w) = 200
l + w = 100
the dimensions are 49 & 51
multiply 49 by 51 = 2499 sq. m, will give the biggest area, any other combinations will give a smaller area if you considered decimal numbers between
