Respuesta :
Answer:
[tex]-1.8<x<-1[/tex] (In Interval Notation: [tex](-1.8,-1)[/tex] )
Step-by-step explanation:
Given the following binomial:
[tex]5x+3[/tex]
You know that if this binomial is in the interval:
[tex](-6, -2)[/tex]
It must be:
[tex]-6<5x+3<-2[/tex]
Therefore, in order to find for what values of "x" the binomial [tex]5x+3[/tex] belongs to the given interval, you need to solve the inequality.
Then, you get:
[tex]-6<5x+3<-2\\\\-6-3<5x<-2-3\\\\-9<5x<-5\\\\\frac{-9}{5}<x<\frac{-5}{5}\\\\-1.8<x<-1[/tex]
Now, you can write this in Interval notation.
Since it is an Open Interval, you must use parentheses. Then, this is:
[tex](-1.8,-1)[/tex]
The values of x for which the binomial 5x+3 belongs to the interval (−6; −2) is given as;
(-1.8; -1)
According to the question, the binomial function 5x + 3 belongs to the interval (-6; -2).
In essence the values of the function lies between -6 and -2.
Mathematically; we have;
- -6 < 5x + 3 < -2
- -6 -3 < 5x < -2 -3
- -9/5 < x < -1
The values of x for which the binomial 5x + 3 belongs to the interval (-6; -2) is given as an inequality;
- -9/5 < x < -5/5
OR
- -1.8 < x < -1
Put differently, this can be written as;
(-1.8; -1)
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