The force on the fry is [tex]0.015 N[/tex]
Explanation:
We can find the force acting on the fry by using Newton's second law:
[tex]F=ma[/tex]
where
F is the net force on the fry
m is its mass
a is its acceleration
For the fry in this problem,
[tex]m=3 g = 0.003 kg[/tex]
[tex]a=5.0 m/s^2[/tex]
Therefore, the force exerted on the fry is
[tex]F=(0.003)(5)=0.015 N[/tex]
Learn more about Newton's second law here:
brainly.com/question/3820012
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