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An object with an initial velocity of 3.2 m/s accelerates at a rate of 1.6 m/s2 for 4 seconds. How far will it have traveled during that time?

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opudodennis

Answer:

25.6 m

Explanation:

From kinetic equation

[tex]s=ut +0.5at^{2}[/tex] where u is initial velocity, a is acceleration and t is time.

Substituting 3.2m/s for u, 1.6m/s2 for a and 4 s for t

[tex]s=3.2*4+0.5(1.6*4^{2})=12.8+12.8=25.6 m[/tex]

Therefore, the distance is 25.6 m

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