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A 65 kg diver is on the 3 meters platform how much energy will she have striking the water below

Respuesta :

opudodennis

Answer:

1912.95  J

Explanation:

Potential energy=mgh where m is mass, g is acceleration due to gravity and h is the height

Substituting  65 Kg for m, 3 m for h and 9.81 m/s2 for g

PE=65*9.81*3=1912.95  J

Therefore, energy of the diver is 1912.95  J

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