Answer:
The gases will expand until a volume of Vf= 10812 cm^3
Explanation:
Since the gas mixture is expanding at constant pressure
[tex]W=\int\limits^{Vf}_{Vi} {P} \, dV =P(Vf-Vi)[/tex]
and therefore
[tex]Vf=W/P+Vi[/tex]
knowing that 1 torr=133,32 Pa
[tex]p=635 torr * 133,322 Pa/torr * 1m^{3}/10^{6}cm^{3}=0,08466 J/ cm^{3}[/tex]
therefore
[tex]Vf=912 J/(0,08466 J/cm^{3}) +40cm^{3} =10812 cm^{3}[/tex]