Answer:
B
Step-by-step explanation:
Our values are:
N = 100,000 (We assume it)
Proportion is p = 0.6
Margin of error (E) = 0.05
confidence-level (cl) = 0.95
Z-value = 1.96
We need to approach through Proportion,
[tex]n=\frac{ (z_2 * p *q) + ME_2}{ME_2 + z_2 * p * q / N}[/tex]
Substituting,
[tex]n = \frac{(1.962*0.6*0.4)+0.052}{0.052 + \frac{1.962 * 0.6 * 0.4}{100000}}[/tex]
[tex]n= \frac{(3.841 * 0.24)+0.0025}{0.0025+\frac{3.841*0.24}{100000}}[/tex]
[tex]n =\frac{ 0.9243}{0.002509}[/tex]
[tex]n= 368[/tex]
