a man whose blood group is heterozygous B is married to a woman whose blood group is also heterozygous B.which of the following statement is correct about the blood group of their four offspring.(A) three of them belong to blood group B,(B) three of them belong to blood group O,(C) none of them belong to blood group O,(D) two of them belong to blood group B.​

Respuesta :

Answer:

A. three of them would belong to blood group B

Explanation:

In a punnet square it would result in:

          B         b

B      BB       Bb

b      Bb       bb

Answer: A three of them belong to blood group B

Explanation:

So one is Bo and the other is also Bo, so then it would lead to BB, Bo, Bo, oo.

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