Answer:
50% efficiency
Explanation:
The efficiency is calculated with the following formula:
[tex]e=\frac{workOut}{workIn}[/tex]
this can also be:
[tex]e=\frac{WorkRequired}{WorkDone}[/tex]
which is more intuitive for the present problem.
the work required, using the definition of work as [tex]W=F*d[/tex] where [tex]F[/tex] is force in newtons, and [tex]d[/tex] is distance in meters.
[tex]WorkRequired:F*d[/tex]
in this case [tex]F=200N[/tex], and [tex]d=2m[/tex], so the work required is:
[tex]WorkRequired:(2000N)*(2m)[/tex]
[tex]WorkRequired:4000J[/tex]
And the work done according to the problem is:
[tex]WorkDone=8000J[/tex]
Thus, the efficiency is:
[tex]e=\frac{WorkRequired}{WorkDone} =\frac{4000J}{8000J} =0.5[/tex]
And since [tex]0.5=50[/tex]%
⇒the answer is that the efficiency of the ramp is 50%
