Answer:
A) One-half of their daughters will have normal color vision and brown eyes; 1/2 of their daughters will have normal color vision and blue eyes.
Explanation:
The genotypes and phenotypes are:
A woman has blue eyes (bb) and normal color vision (she has an Xᴰ chromosome) but her father was color-blind, so the other X chromosome she has carries the recessive d allele. She has the genotype bb XᴰXᵈ.
The man has normal color vision (he is XᴰY) and has brown eyes, but his mother had blue eyes so he must have inherited a b allele from her and is therefore heterozygous Bb. His genotype is BbXᴰY.
The blue/brown eyes gene is autosomal and independent from the sex-linked color blindness gene.
The woman can produce the gametes b Xᴰ and b Xᵈ.
The man can produce the gametes B Xᴰ, b Xᴰ, B Y and bY.
The female daughters can have the following genotypes and phenotypes: