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A flowerpot falls from the ledge of an apartment building. A person in an apartment below, coincidentally holding a stopwatch, notices that it takes 1 s for the pot to fall past his window, which is 4 m high. How far above the top of the window is the ledge from which the pot fell? The acceleration of gravity is 9.81 m/s 2 . Answer in units of m.

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Answer

given,

height of window = 4 m

time taken to travel = 1 s

acceleration due to gravity = 9.8 m/s²

[tex]s = ut + \dfrac{1}{2}at^2[/tex]

[tex]u = \dfrac{s - \dfrac{1}{2}at^2}{t}[/tex]

[tex]u = \dfrac{4 - \dfrac{1}{2}\times 9.8\times 1^2}{1}[/tex]

u = -0.905 m/s

initial velocity of ledge v = 0

now,

v² = u² + 2 a s

(-0.905)² = 0 + 2 × 9.8 ×s

s = 0.042 m

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