Respuesta :
Answer:
In 6% of the projects was Bautista selected, but Aaron was not
Step-by-step explanation:
Building the Venn diagram, I am going to say that:
-A is the number of projects that Aaron was selected.
-B is the number of projects that Bautista was selected.
We have that:
[tex]A = a + (A \cap B)[/tex]
In which a is the number of projects that only Aaron was selected and [tex]A \cap B[/tex] is the number of projects that both were selected.
By the same logic, we also have that:
[tex]B = b + (A \cap B)[/tex]
In what percentage of the projects was Bautista selected, but Aaron was not
There were b projects that Bautista was selected and Aaron not. The total number projects is 50. So this percentage is b/50.
We start finding the values from the intersection.
12 of the projects, they both were selected. This means that [tex]A \cap B = 12[/tex]
Bautista was selected for 15 of the projects, so [tex]B = 15[/tex]
[tex]B = b + (A \cap B)[/tex]
[tex]15 = b + 12[/tex]
[tex]b = 3[/tex]
--------
[tex]P = \frac{3}{50} = 0.06[/tex].
In 6% of the projects was Bautista selected, but Aaron was not
