Answer:
a) v = √(GM/R), b)  K = ½ G m M /R and d)  T = 2π R√(R/GM)
Explanation:
This problem should use the law of universal gravitation
  F = G m M / r²
a) For this part we use Newton's second law where acceleration is centripetal
  F = m a
Centripetal acceleration is
  a = v² / r
  F = m v² / r
  G m M / r² = m v² / r
  G M / r = v²
We use the distance (R) measured from the center of the planet
  v = √(GM / R)
b) the expression for kinetic energy is
  K = ½ m v²
  K = ½ m G M / R
  K = ½ G m M / R
d) as the velocity module is constant, we can use the equation and uniform motion
  v = d / T
  T = d / v
The distance is the length of the circle
  d = 2π R
  T = 2π R / √(GM / R)
  T = 2π R √ (R / GM)