Respuesta :
Answer:
2 L, L, 2 L/3
Explanation:
For a pipe of length l open at both ends, the length of the pipe is given by :
[tex]l=\dfrac{n\lambda}{2}[/tex]
or
[tex]\lambda=\dfrac{2l}{n}[/tex]
For first pitch tone, n = 1
[tex]\lambda_1=2l[/tex]
For first pitch tone, n = 2
[tex]\lambda_2=\dfrac{2l}{2}[/tex]
[tex]\lambda_2=l[/tex]
For first pitch tone, n = 3
[tex]\lambda_3=\dfrac{2l}{3}[/tex]
[tex]\lambda_3=\dfrac{2l}{3}[/tex]
So, the wavelengths of the three lowest-pitch tones produced by this pipe are 2 L, L, 2 L/3 respectively. Hence, the correct option is (d)
Answer:
2 L, L, 2 L/3
Explanation:
For a pipe of length l open at both ends, the length of the pipe is given by :
or
For first pitch tone, n = 1
For first pitch tone, n = 2
For first pitch tone, n = 3
So, the wavelengths of the three lowest-pitch tones produced by this pipe are 2 L, L, 2 L/3 respectively. Hence, the correct option is (d)