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The energy required to dislodge electrons from cesium metal via the photoelectric effect is 207 kJ/mol . What wavelength (in nm) of light has sufficient energy per photon to dislodge an electron from the surface of cesium?

Respuesta :

Answer:

So wavelength in nm will be [tex]\lambda =0.956\times 10^{-19}nm[/tex]    

Explanation:

We have given that the energy = 207 KJ/mol [tex]=207\times 10^3j/mol[/tex]

Speed of light [tex]c=3\times 10^8m/sec[/tex]

Plank's constant [tex]h=6.6\times 10^{-34}J-s[/tex]

According to plank's rule energy of the photon is given by

[tex]E=\frac{hc}{\lambda }[/tex]

[tex]207\times 10^3=\frac{6.6\times 10^{-34}\times 3\times 10^8}{\lambda }[/tex]

[tex]\lambda =0.956\times 10^{-28}m[/tex]

So wavelength in nm will be [tex]\lambda =0.956\times 10^{-19}nm[/tex]

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