Answer:
0.2334
Step-by-step explanation:
We know that 30% are conservatives, so that is our proportion.
We define then,
p=0.30
n=0.7 (probability to not be conservative)
Our sample size (n) is 10.
So need to find if three of them are conservatives
This a typical binomial distribution
[tex]p(\pi)= ^{m}c_{\pi}p*n^{m-\pi}[/tex]
Here [tex]\pi=2[/tex], (you can be either conservative or not conservative)
[tex]p(2)=^{10}c_2*(0.3)^2(0.7)^{10-2}\\p(2)=(\frac{10*9}(2))*(0.3)*(0.7)^{10-2}\\p(2)=0.2334[/tex]
