Answer:
The width of the room is [tex]6\frac{2}{5}[/tex].
Step-by-step explanation:
Consider the provided information.
It is given that the whole room has an area 46 14/15 sq yd.
This can be written as:
[tex]46\frac{14}{15}=\frac{704}{15}[/tex] yd.
Now consider the figure shown below:
From the figure we know that the length of the rectangular meeting room is [tex]7\frac{1}{3}[/tex] yd.
[tex]7\frac{1}{3}=\frac{22}{3}[/tex]
The area of rectangle is [tex]A=l\times w[/tex]
Let width of the rectangle is w yard.
[tex]\frac{704}{15}=\frac{22}{3}\times w[/tex]
[tex]w=\frac{704}{15}\times \frac{3}{22}[/tex]
[tex]w=\frac{32}{5}=6\frac{2}{5}[/tex]
Hence, the width of the room is [tex]6\frac{2}{5}[/tex].
