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How many solutions exist for the given equation? StartFraction one-half left-parenthesis x plus 12 right-parenthesis equals 4 x minus 1.(x + 12) = 4x – 1 zero one two infinitely many

Respuesta :

frika

Answer:

One solution x = 2

Step-by-step explanation:

Given the equation:

[tex]\dfrac{1}{2}(x+12)=4x-1[/tex]

Multiply this equation by 2:

[tex]2\cdot \dfrac{1}{2}(x+12)=2\cdot (4x-1)\\ \\x+12=2(4x-1)[/tex]

Use distributive property:

[tex]x+12=8x-2[/tex]

Combine the like terms:

[tex]x+12=8x-2\\ \\x+12-12=8x-2-12\\ \\x=8x-14\\ \\x-8x=8x-14-8x\\ \\-7x=-14\\ \\7x=14\\ \\x=2[/tex]

Thus, this equation has one solution x = 2

Answer:

its one

Step-by-step explanation:

edge

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