Answer:
V₂ = 123.5 L
Explanation:
Given data:
Initial volume = 135 L
Initial temperature = 21.0 °C
Final volume = ?
Final temperature = -4°C
Solution:
-4+273 = 269 k
21.0+273 = 294 k
V₁/T₁ = V₂/T₂
V₂ = V₁.T₂/ T₁
V₂ = 135 L . 269 K / 294 K
V₂ = 36315 L . K / 294 K
V₂ = 123.5 L
