Respuesta :
Answer:
Part a:
a) t (°C) =  100°C
b) t (°C) =  20°C
c) t (°C) =  197°C
Part b:
a) T = 273 K
b) T = 523 K
c) T = 3003 K
Explanation:
Data Given
Temperature given in Kelvin.
1) 373k
2) 293K
3) 470K
Hint:
t = T - 273
Temperature given Celsius
a) 0C
b) 250C
c) 2730C
Hint : T = 273 + t
Solution:
In the first prat of the question we have to convert temperature from kelvin to Celsius scale.
As the hint given in this question is given as
         t = T - 273
This is derived from the Formula
       T = t (°C) + 273 . . . . . . . . .. . . .  (1)
where
T = is the Kelvin temperature
t = is the Celsius temperature
So, to convert the K to °C, we rearrange the equation (1)
            t (°C) =  T - 273 . . . . . . . . . . . . . . (2)
Now put the value in equation 2
a) 373 K
        t (°C) =  T - 273
        t (°C) =  373 - 273
        t (°C) =  100°C
__________________________
b) 293 K
        t (°C) =  T - 273
        t (°C) =  293 - 273
        t (°C) =  20°C
__________________________
c) 470 K
        t (°C) =  T - 273
        t (°C) =  470 - 273
        t (°C) =  197°C
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In the 2nd prat of the question we have to convert temperature from Celsius scale to kelvin.
As the hint given in this question is given as
    T = 273 + t
This is the Formula
       T = t (°C) + 273 . . . . . . . . .. . . .  (1)
where
T = is the Kelvin temperature
t = is the Celsius temperature
Now put the value in equation 1
a) 0°C
          T = t (°C) + 273
          T = 0 + 273
          T = 273 K
_____________________________
b) 250°C
          T = t (°C) + 273
          T = 250 + 273
          T = 523 K
_____________________________
c) 2730°C
          T = t (°C) + 273
          T = 2730 + 273
          T = 3003 K
_____________________________
