For this case we have that by definition, the equation of the line of the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It is the slope of the line
b: It is the cut-off point with the y axis
We have the following equation:
[tex]y = - \frac {1} {5} x-3[/tex]
So we have to:
The slope is:[tex]m = - \frac {1} {5}[/tex]
The cut-off point with the y axis is:[tex]b = -3[/tex]
Answer:
The slope is: [tex]m =- \frac {1} {5}[/tex]
The cut-off point with the y axis is: [tex]b = -3[/tex]
