Answer:
V₁ = 0.35 L
Explanation:
Given data:
Molarity of calcium hydroxide = 0.0355 M
Volume of aluminium sulfate = 50.0 mL ( 50/1000 = 0.05 L)
Molarity of aluminium sulfate = 0.250 M
Volume of calcium hydroxide = ?
Solution:
M₁V₁ = M₂V₂
V₁ = M₂V₂ / M₁
V₁ = 0.250 M . 0.05 L / 0.0355 M
V₁ = 0.0125 M.L/ 0.0355 M
V₁ = 0.35 L
