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2 co (g) + C (g) -> C3O2 (g)
delta h = 127.3 kJ/mol (rxn)
the equation above represents an endothermic reaction between CO(g) and C(g). What is the amount of heat absorbed when 1.00 mol of Co reacts with an excess C?

a) 31.8 kJ
b)63.7 kJ
c)127.3 kJ
d)254.6 kJ

Respuesta :

Answer:

b) 63.7 kJ

Explanation:

     [tex]2 CO_{(g)}  + C _{(s)} ----> C_{3}O_{2}[/tex]

we have ΔH = 127.3 kJ/mol  

for 1.00 mole of CO the equation can be re-written as,

[tex]CO_{(g)}  +\frac{1}{2}  C _{(s)} ---->\frac{1}{2}  C_{3}O_{2}[/tex]

since the number of moles are halved  ΔH also gets halved as per Hesse's law of constant summation,

ΔH =   [tex]\frac{127.3}{2}[/tex]  

      =  63.7 kJ

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