Answer:
    T = 0.946 N
Explanation:
there are four tension forces making an angle θ where θ = 5.0
side of the length l = 0.01 m
Area A = 0.01 * 0.01 m
       = 1.0*10^-4 m^2
Pressure inside the bladder is P = 3300 Pa
      ( 3300 Pa ) ( 1.0*10^-4 m^2  = 4 T sin (5.0 )
      T = 0.946 N