Answer:
P = 28.1 atm
Explanation:
Given data:
Mass of carbon dioxide = 25 g
Temperature = 27.0 °C
Volume = 500 mL
Pressure = ?
Solution:
Number of moles = mass/ molar mass
Number of moles = 25.0 g/ 44 g/mol
Number of moles = 0.57 mol
PV = nRT
P = nRT/V
P = 0.57 mol × 0.0821 atm.L.mol⁻¹.K⁻¹ × 300 k/ 0.5 L
P = 14.1 atm. L /0.5 L
P = 28.1 atm
