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An 80 kg skateboarder moving at 3 m/s pushes off with her back foot to move faster.
If her velocity increases to 5 m/s, what is her change in kinetic energy as a result?
 J
How much work did she perform?
 J
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Respuesta :

MathPhys

Answer:

640 J

640 J

Explanation:

ΔKE = ½ mv² − ½ mu²

ΔKE = ½ m (v² − u²)

ΔKE = ½ (80 kg) ((5 m/s)² − (3 m/s)²)

ΔKE = 640 J

Work = ΔE

Work = 640 J

samanthafoster43

Answer:

640 for both

Explanation:

got right on edg

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