Answer:
60.80 g
Explanation:
BaCl₂ (aq) + K₂CrO₄ (aq) → BaCrO₄ (s) + 2 KCl (aq)
For the reaction , given in the question ,
1 mol of BaCl₂ reacts with 1 mol of K₂CrO₄ to give the corresponding products .
Hence , from the question ,
0.41 mol of BaCl₂ requires 0.41 mol of K₂CrO₄
But , only 0.24mol of K₂CrO₄ are available ,
Therefore ,
K₂CrO₄ act as a limiting reagent , and will decide the product of the reaction ,
Hence , from the reaction ,
1 mol K₂CrO₄ gives , 1 mol BaCrO₄ ,
Hence ,
0.24 mol of K₂CrO₄ , will give 0.24 mol of BaCrO₄ .
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
0.24 mol of BaCrO₄ ,
therefore ,
m = molecular mass of BaCrO₄ = 253.37 g/mol
n = w / m
w = n * m
w = 0.24 mol * 253.37 g/mol = 60.80 g
