Answer:
[tex]\large\boxed{square\ root\ of\ -16=\pm4i}[/tex]
Step-by-step explanation:
[tex]i=\sqrt{-1}\\\\\sqrt{-16}=\sqrt{(16)(-1)}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt{16}\cdot\sqrt{-1}=\pm4\cdot i=\pm4i[/tex]
