Answer:
2.40 kPa
Explanation:
Given data:
radius or width of the cylinder d= 9.7 cm
radius r= 4.85 cm
height h= 12 cm
force applied from the piston F= 18 N
Area of the cross section of cylinder A=Ï€r^2
[tex]= \pi (0.0485)^2[/tex]= 0.007386 [tex]m^2[/tex]
now, pressure P= Force / Area
[tex]P= \frac{18}{0.007386}[/tex]
= 2437.04 [tex]\frac{N}{m^2}[/tex]
= 2.437 kPa
correct to two significant figure = 2.40 kPa